0=-16x^2-5x+450

Solution for 0=-16x^2-5x+450 equation:

0=-16x^2-5x+450

We move all terms to the left:

0-(-16x^2-5x+450)=0

We add all the numbers together, and all the variables

-(-16x^2-5x+450)=0

We get rid of parentheses

16x^2+5x-450=0

a = 16; b = 5; c = -450;
Δ = b2-4ac
Δ = 52-4·16·(-450)
Δ = 28825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28825}=\sqrt{25*1153}=\sqrt{25}*\sqrt{1153}=5\sqrt{1153}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5\sqrt{1153}}{2*16}=\frac{-5-5\sqrt{1153}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5\sqrt{1153}}{2*16}=\frac{-5+5\sqrt{1153}}{32}
$